In the give first-order sequential reactions: A → B (K1) → C (K2) → D (K3), what is the ratio of number of atoms of A to the number of atoms of B after long time interval starting with pure A? (K1 = l

Question

In the give first-order sequential reactions: A → B (K1) → C (K2) → D (K3), what is the ratio of number of atoms of A to the number of atoms of B after long time interval starting with pure A? (K1 = ln 2 / 1200 and K2 = ln 2 / 30)

Prashant Kotian · Accepted Answer

Correct answer: D. B is a highly reactive intermediate (K2 >> K1). Applying steady state approximation to B: d[B]/dt = K1[A] - K2[B] ≈ 0 => [A]/[B] = K2 / K1 = (ln 2 / 30) / (ln 2 / 1200) = 1200 / 30 = 40. Therefore, correct answer is D.

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