For the series of competitive reactions: H + HO2 → H2 + O2 (k1); H + HO2 → 2OH (k2); H + HO2 → H2O + O (k3). It has been found that K1:K2:K3 = 0.60:0.30:0.10. The molar ratio of the products, H2, O2,

Question

For the series of competitive reactions: H + HO2 → H2 + O2 (k1); H + HO2 → 2OH (k2); H + HO2 → H2O + O (k3). It has been found that K1:K2:K3 = 0.60:0.30:0.10. The molar ratio of the products, H2, O2, OH, H2O and O, at time, t, is

Prashant Kotian · Accepted Answer

Correct answer: A. Reaction 1 produces 1 H2 and 1 O2 (rate 0.6). Reaction 2 produces 2 OH (rate 0.3, so OH produced 0.6). Reaction 3 produces 1 H2O and 1 O (rate 0.1). Ratio is 0.6 : 0.6 : 0.6 : 0.1 : 0.1 = 6:6:6:1:1. Therefore, correct answer is A.

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