Chemical KineticshardMCQ SINGLE

The rate expression for a reaction is -dC/dt = (α.C) / (1 + βC), where α, β are constants and C is tChemical Kinetics Chemistry Question

Question

The rate expression for a reaction is -dC/dt = (α.C) / (1 + βC), where α, β are constants and C is the concentration of reactant at time, t. The half-life for this reaction is

Answer: A

💡 Solution & Explanation

Rearranging to -(1 + βC)/C dC = α dt and integrating from C0 to C0/2 yields (ln 2) + β(C0/2) = α t_1/2. Solving for t_1/2 gives (ln 2)/α + (β C0)/(2α). Therefore, correct answer is A.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry