The initial rate of hydrolysis of methyl acetate (1.0 M) by a weak acid (HA, 1.0 M) is 1/100th of that of a strong acid (HX, 1.0 M), at 25°C. The Ka of HA is

Question

Prashant Kotian · Accepted Answer

Correct answer: A. Rate is proportional to [H+]. [H+] from HA / [H+] from HX = 1/100. Since HX is a strong acid, [H+] = 1.0 M, so [H+] from HA = 0.01 M. For a weak acid, [H+]^2 = Ka × C => (0.01)^2 = Ka × 1.0 => Ka = 10^-4. Therefore, correct answer is A.

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