If 1% of a substance undergoing decomposition is consumed in 1 min, when the concentration is 0.02 M — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

The time for a small fractional completion (like 1%) is proportional to the half-life. t_1% ∝ [A0]^(1-n). (1 min / 0.25 min) = (0.02 / 0.04)^(1-n) => 4 = (1/2)^(1-n) = 2^(n-1). Thus, n-1 = 2, giving n = 3. Therefore, correct answer is A.