SO2Cl2 → SO2 + Cl2 is a first-order gaseous reaction with K = 2.5 × 10^-5 s^-1 at 320°C. The percentage of SO2Cl2 decomposed on heating for 100 min is (ln 1.16 = 0.15)

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Prashant Kotian · Accepted Answer

Correct answer: D. kt = 2.5 × 10^-5 s^-1 × (100 × 60) s = 0.15. ln(A0/A) = 0.15 = ln(1.16). So, A0/A = 1.16 => A = A0 / 1.16 ≈ 0.862 A0. Fraction decomposed = (A0 - A)/A0 = 1 - 0.862 = 0.138 = 13.8%. Therefore, correct answer is D.

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