Rate of the chemical reaction: A → products, is doubled, when the concentration of 'A' is increased four times. If the half-life of the reaction is 16 min, at a given concentration, then the time requ

Question

Rate of the chemical reaction: A → products, is doubled, when the concentration of 'A' is increased four times. If the half-life of the reaction is 16 min, at a given concentration, then the time required for 75% of the reaction to complete is

Prashant Kotian · Accepted Answer

Correct answer: B. Rate doubles when conc quadruples implies n = 0.5. For n = 0.5, t = (C0^0.5 - C^0.5) / (0.5K). t_1/2 = C0^0.5(1 - 1/sqrt(2))/(0.5K) = 16. t_75% = C0^0.5(1 - 1/2)/(0.5K). Ratio t_75% / t_1/2 = 0.5 / (1 - 0.707) ≈ 1.706. t_75% = 1.706 * 16 = 27.3 min. Therefore, correct answer is B.

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