Chemical KineticsmediumMCQ SINGLE

A solution of N2O5 in CCl4 yields by decomposition at 45°C, 4.8 ml of O2, 20 min after the start of Chemical Kinetics Chemistry Question

Question

A solution of N2O5 in CCl4 yields by decomposition at 45°C, 4.8 ml of O2, 20 min after the start of the experiment and 9.6 ml of O2 after a very long time. The decomposition obeys first-order kinetics. What volume of O2 would have evolved, 40 min after the start?

Answer: A

💡 Solution & Explanation

The total volume after a long time is 9.6 ml. After 20 min, 4.8 ml is produced, which is exactly half of the total (50% decomposition). Hence, t1/2 = 20 min. After 40 min (2 half-lives), 75% will be decomposed. Volume = 0.75 × 9.6 = 7.2 ml. Therefore, correct answer is A.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry