The chemical reaction: 2O3 → 3O2 proceeds as O3 ⇌(K1/K2) O2 + O (fast), O + O3 --(K3)-- 2O2 (slow). The rate law expression will be

Question

The chemical reaction: 2O3 → 3O2 proceeds as O3 ⇌(K1/K2) O2 + O (fast), O + O3 --(K3)--> 2O2 (slow). The rate law expression will be

Prashant Kotian · Accepted Answer

Correct answer: C. The rate is determined by the slow step: rate = K3[O][O3]. From the fast equilibrium, K1/K2 = [O2][O] / [O3], giving [O] = (K1[O3]) / (K2[O2]). Substituting this into the rate equation yields rate = K3 (K1[O3] / K2[O2]) [O3] = (K1 K3 / K2) * [O3]^2 / [O2]. Therefore, correct answer is C.

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