In a study of effect of temperature on reaction rate, the value of (1/K) dK/dT is found to be (1.25 — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

d(ln K)/dT = Ea / RT^2, so Ea = R × (1.25 × 10^6) / T. At 250 K, Ea = 2 × 1.25 × 10^6 / 250 = 10,000 cal/mol = 10 kcal/mol. At 2000 K, Ea = 1.25 kcal/mol. The T^3 denominator in the derivative dictates a steeper rate of change at lower temperatures. At 1000 K, d(ln K)/dT is 1.25 × 10^-3, not 0.625. Therefore, correct answer is A,B,C.