When secondary alkyl halide undergo SN reaction, it follow SN1 (first-order) and SN2 (second-order) pathway simultaneously. An alkyl halide undergoes both pathway with rate constants 3 × 10^-4 s^-1 an

Question

When secondary alkyl halide undergo SN reaction, it follow SN1 (first-order) and SN2 (second-order) pathway simultaneously. An alkyl halide undergoes both pathway with rate constants 3 × 10^-4 s^-1 and 5 × 10^-4 M^-1 s^-1, respectively. Which of the following is/are correct information for the reaction?

Prashant Kotian · Accepted Answer

Correct answer: A,B,C,D. Rate_SN1 = 3 × 10^-4 [RX]. Rate_SN2 = 5 × 10^-4 [RX][Nu]. (A) At [Nu]=0.1, Rate_SN2 = 0.5 × 10^-4 (SN1 dominates). (B) At [Nu]=1.0, Rate_SN2 = 5 × 10^-4 (SN2 dominates). (C) At [Nu]=0.6, Rate_SN2 = 3 × 10^-4, rates are equal, so 50% SN1. (D) At [Nu]=0.9, Rate_SN2 = 4.5 × 10^-4. Total rate proportional to 7.5 × 10^-4. % SN1 = 3 / 7.5 = 40%. Therefore, correct answer is A,B,C,D.

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