The rate law for the reaction: RCl + NaOH(aq) → ROH + NaCl is given by, rate = K1[RCl]. The rate of the reaction will be 1. Doubled on doubling the concentration of NaOH 2. Halved on reducing the conc

Question

The rate law for the reaction: RCl + NaOH(aq) → ROH + NaCl is given by, rate = K1[RCl]. The rate of the reaction will be 1. Doubled on doubling the concentration of NaOH 2. Halved on reducing the concentration of alkyl halide to one half 3. Increased on increasing the temperature of the reaction 4. Unaffected by increasing the temperature of the reaction

Prashant Kotian · Accepted Answer

Correct answer: D. The reaction is first-order with respect to RCl and zero-order with respect to NaOH. Doubling NaOH has no effect. Halving RCl halves the rate. Increasing temperature increases the rate constant and hence the rate. Thus, statements 2 and 3 are correct. Therefore, correct answer is D.

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