SO3 gas is entering the environment at a constant rate of 6.93 × 10^-6 g/ l/day due to emission of polluting gases from thermal power plant at Kota, but at the same time it is decomposing and followin

Question

SO3 gas is entering the environment at a constant rate of 6.93 × 10^-6 g/ l/day due to emission of polluting gases from thermal power plant at Kota, but at the same time it is decomposing and following first-order kinetics with half-life of 100 days. Based on these details, select the correct statement(s) from the following:

Prashant Kotian · Accepted Answer

Correct answer: A,D. At steady state, Rate of formation = Rate of decomposition. 6.93 × 10^-6 g/L/day / 80 g/mol = K [SO3]. K = 0.693/100 day^-1. [SO3] = (6.93 × 10^-6 / 80) / (6.93 × 10^-3) = 1.25 × 10^-5 M. After 1000 days (10 half-lives), concentration reduces by 2^10 ≈ 1000, so 1.25 × 10^-8 M. Therefore, correct answer is A,D.

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