For the first-order consecutive reactions: A --K1-- B --K2-- C, the reaction is started with some amount of only 'A'. Match the Column I (observations) with Column II (time) related with reactions.

Question

For the first-order consecutive reactions: A --K1--> B --K2--> C, the reaction is started with some amount of only 'A'. Match the Column I (observations) with Column II (time) related with reactions.

Prashant Kotian · Accepted Answer

Correct answer: A-P,Q, B-P,R, C-S. (A) Rate of formation of C is K2[B], maximum when [B] is maximum. t_max = 1/(K2-K1)ln(K2/K1) (Q). If K2=2K1, this simplifies to ln(2)/K1 = t_1/2 of A (P). (B) [B] = [C] at t=0 (rate of formation of B is max here, R). Also at t_1/2 of A if K2=2K1, [B]=[C]=A0/4 (P). (C) Equating [A]_t = [B]_t simplifies algebraically directly to t = 1/(K1-K2)ln((2K1-K2)/K1) (S). Therefore, correct answer is A-P,Q, B-P,R, C-S.

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