The gas phase decomposition of acetic acid at 1189 K proceeds by way of two parallel reactions:
CH3COOH → CH4 + CO2, K1 = 3.2 s^-1
CH3COOH → H2C=C=O + H2O, K2 = 4.8 s^-1
The maximum percentag

Question

The gas phase decomposition of acetic acid at 1189 K proceeds by way of two parallel reactions:
CH3COOH → CH4 + CO2, K1 = 3.2 s^-1
CH3COOH → H2C=C=O + H2O, K2 = 4.8 s^-1
The maximum percentage yield of the ketene, CH2CO, obtainable at this temperature, is

Prashant Kotian · Accepted Answer

Correct answer: 0060. In parallel first-order reactions, the percentage yield of a specific product is given by the ratio of its formation rate constant to the total rate constant. Yield % = (K2 / (K1 + K2)) × 100% = (4.8 / (3.2 + 4.8)) × 100% = (4.8 / 8.0) × 100% = 60%. Therefore, correct answer is 0060.

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