The rate constant for the decomposition of ozone following second-order kinetics is 5 × 10^-4 l mol^-1 s^-1 at a certain temperature. The rate of reaction (in terms of number of molecules decomposed p

Question

The rate constant for the decomposition of ozone following second-order kinetics is 5 × 10^-4 l mol^-1 s^-1 at a certain temperature. The rate of reaction (in terms of number of molecules decomposed per ml per minute, when concentration of ozone is 2 × 10^-8 M, is (N_A = 6 × 10^23)

Prashant Kotian · Accepted Answer

Correct answer: 07200. Rate = k[O3]^2 = 5 × 10^-4 × (2 × 10^-8)^2 = 2 × 10^-19 mol L^-1 s^-1. To convert to molecules ml^-1 min^-1: Rate = 2 × 10^-19 × (1/1000) × 60 × (6 × 10^23) = 2 × 10^-19 × 0.06 × 6 × 10^23 = 7200 molecules ml^-1 min^-1. Therefore, correct answer is 07200.

💡 Solution & Explanation

Practice 22,000+ questions like this