If activation energy of a reaction is 83.14 kJ/mole, the fraction of molecules at 500 K which have e — Chemical Kinetics Chemistry Question
Question
If activation energy of a reaction is 83.14 kJ/mole, the fraction of molecules at 500 K which have enough energy to form products is x × 10^-y. The value of (y - x) is (ln 2 × 10^-9 = -20, ln 4 × 10^-5 = -10, ln 4 × 10^-18 = -40)
Answer: 7
💡 Solution & Explanation
Fraction = e^(-Ea/RT) = e^(-83140 / (8.314 × 500)) = e^(-10000 / 500) = e^-20. Using the hint provided in the problem statement (ln(2 × 10^-9) = -20), this means e^-20 = 2 × 10^-9. Thus, x = 2 and y = 9. The value of (y - x) = 9 - 2 = 7. Therefore, correct answer is 7.
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