Consider two first-order reactions I and II. The frequency factor of I is 100 times that of II, the activation energy of I is 4.606 kcal higher than that of II. If the ratio of rate constants for the

Question

Consider two first-order reactions I and II. The frequency factor of I is 100 times that of II, the activation energy of I is 4.606 kcal higher than that of II. If the ratio of rate constants for the reactions I and II is x:1, at 227°C, the value of x is

Prashant Kotian · Accepted Answer

Correct answer: 1. Ratio of rate constants k1/k2 = (A1/A2) * e^-(Ea1 - Ea2)/RT. We know A1/A2 = 100. Ea1 - Ea2 = 4606 cal. Temperature T = 227 + 273 = 500 K, so RT = 2 * 500 = 1000 cal. The exponential term is e^(-4606/1000) = e^-4.606. Converting base: e^-4.606 = 10^(-4.606/2.303) = 10^-2 = 1/100. k1/k2 = 100 * (1/100) = 1. Therefore, correct answer is 1.

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