In the reaction: A → Products, the rate is doubled when the concentration of 'A' is quadrupled. If 50% of the reaction occurs in 8√2 h, how long (in hours) would it take for the completion of next 50%

Question

In the reaction: A → Products, the rate is doubled when the concentration of 'A' is quadrupled. If 50% of the reaction occurs in 8√2 h, how long (in hours) would it take for the completion of next 50% reaction?

Prashant Kotian · Accepted Answer

Correct answer: 8. Rate quadrupled implies order n = 1/2. For n = 1/2, the half-life t1/2 is proportional to √A0. The first 50% takes 8√2 h. The "next 50%" reaction operates on the remaining half of the initial concentration (A0/2). Its half-life will be scaled by √(1/2). Thus, new time = 8√2 × (1/√2) = 8 h. Therefore, correct answer is 8.

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