For the reaction: A(g) → nB(g), rate constant is 6.93 × 10^-4 s^-1. The reaction is performed at con — Chemical Kinetics Chemistry Question
Question
For the reaction: A(g) → nB(g), rate constant is 6.93 × 10^-4 s^-1. The reaction is performed at constant volume and temperature, starting with pure A(g). If after 1000 s from the start of reaction, the pressure of system becomes 3 times the initial pressure, the value of n is
Answer: 5
💡 Solution & Explanation
Half-life t1/2 = 0.693 / (6.93 × 10^-4) = 1000 s. After 1000 s (one half-life), exactly half of A has reacted. Total pressure P = P0 - 0.5P0 + 0.5nP0 = P0(0.5 + 0.5n). Given P = 3P0, we get 0.5 + 0.5n = 3 => 0.5n = 2.5 => n = 5. Therefore, correct answer is 5.
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