A viral preparation was inactivated in a chemical bath. The inactivation process was found to be first order in virus concentration and at the beginning of the experiment, 2.0% of the virus was found

Question

A viral preparation was inactivated in a chemical bath. The inactivation process was found to be first order in virus concentration and at the beginning of the experiment, 2.0% of the virus was found to be inactivated per minute. If the rate constant for the inactivation process is K min^-1, then the value of 400 K is

Prashant Kotian · Accepted Answer

Correct answer: 8. The initial rate of fraction inactivated per minute gives the rate constant directly for very small changes. Rate = k[A]. 0.02[A] / min = k[A] => k = 0.02 min^-1 (or rigorously, k = ln(100/98) ≈ 0.02). The value of 400 K = 400 × 0.02 = 8. Therefore, correct answer is 8.

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