For the reaction: 2NO(g) + H2(g) → N2O(g) + H2O(g), the value of -dP/dt was found to be 1.5 Pa s^-1 for a pressure of 372 Pa for NO and 0.25 Pa s^-1 for a pressure of 152 Pa for NO, the pressure of H2

Question

For the reaction: 2NO(g) + H2(g) → N2O(g) + H2O(g), the value of -dP/dt was found to be 1.5 Pa s^-1 for a pressure of 372 Pa for NO and 0.25 Pa s^-1 for a pressure of 152 Pa for NO, the pressure of H2 being constant. If pressure of NO was kept constant, the value of -dP/dt was found 1.60 Pa s^-1 for a pressure of 289 Pa for H2 and 0.79 Pa s^-1 for a pressure of 144 Pa for H2. If the order of reaction with respect to NO and H2 are a and b, respectively, then the value of (a + b) is

Prashant Kotian · Accepted Answer

Correct answer: 3. For NO: Rate ratio = 1.5 / 0.25 = 6. Pressure ratio = 372 / 152 = 2.447. 2.447^a = 6 implies a = 2. For H2: Rate ratio = 1.60 / 0.79 = 2.025. Pressure ratio = 289 / 144 = 2.007. 2.0^b = 2.025 implies b = 1. Overall order = a + b = 2 + 1 = 3. Therefore, correct answer is 3.

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