Temperature at which the net activation energy for the dissociation of 'X' will be 10.5 kcal/mol, is — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Net Ea = (K1 Ea1 + K2 Ea2) / (K1 + K2). For net Ea = 10.5 (exactly halfway between 12 and 9), K1 must equal K2. Setting 2×10^14 e^(-12000/RT) = 2×10^14 e^-2 e^(-9000/RT) gives -12000/RT = -2 - 9000/RT, leading to 3000/RT = 2. With R ≈ 2 cal/K-mol, T = 3000 / (2 × 2) = 750 K. Therefore, correct answer is B.