In what time, the concentration of 'B' will become maximum? — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

The time for maximum concentration of intermediate B is t_max = ln(K2/K1) / (K2 - K1) = ln(0.06/0.04) / (0.06 - 0.04) = ln(1.5) / 0.02 = (ln 3 - ln 2) / 0.02. Given e^0.7 = 2 (ln 2 = 0.7) and e^1.1 = 3 (ln 3 = 1.1), t_max = (1.1 - 0.7) / 0.02 = 0.4 / 0.02 = 20 min. Therefore, correct answer is B.