What is the rate, mol l^-1 s^-1, at the instant when [OH] = 1.7 × 10^-8 M and [H2S] = 1.0 × 10^-8 M? — Chemical Kinetics Chemistry Question
Question
What is the rate, mol l^-1 s^-1, at the instant when [OH] = 1.7 × 10^-8 M and [H2S] = 1.0 × 10^-8 M?
Answer: C
💡 Solution & Explanation
Rate = K[OH][H2S] = (5.128 × 10^9) × (1.7 × 10^-8) × (1.0 × 10^-8) = 8.71 × 10^-7 mol L^-1 s^-1. Therefore, correct answer is C.
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