What is the rate, mol l^-1 s^-1, at the instant when [OH] = 1.7 × 10^-8 M and [H2S] = 1.0 × 10^-8 M? — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Rate = K[OH][H2S] = (5.128 × 10^9) × (1.7 × 10^-8) × (1.0 × 10^-8) = 8.71 × 10^-7 mol L^-1 s^-1. Therefore, correct answer is C.