What is the initial rate of formation of HBr, +d[HBr]/dt? — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

At the initial stage of the reaction (t = 0), the concentration of product [HBr] is zero. Substituting [HBr] = 0 into the rate law denominator (K3[Br2] + K4[HBr]) simplifies it to K3[Br2]. The [Br2] terms partially cancel, yielding Rate = 2K2(K1/K5)^1/2 [H2][Br2]^1/2. Therefore, correct answer is A.