If rate of formation of O2 is 16 g/h, then rate of decomposition of N2O5 and rate of formation of NO — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Rate of O2 formation = 16 g/h = 16/32 mol/h = 0.5 mol/h. Rate of N2O5 decomposition = 2 × 0.5 = 1.0 mol/h = 1.0 × 108 g/h. Rate of NO2 formation = 4 × 0.5 = 2.0 mol/h = 2.0 × 46 = 92 g/h. Therefore, correct answer is A.