Solutions and Colligative PropertiesmediumMCQ SINGLE

Ice begins to separate at from an aqueous solution containing 2.4 g of a non-volatile, non-electrolySolutions and Colligative Properties Chemistry Question

Question

Ice begins to separate at $-0.744^\circ\text{C}$ from an aqueous solution containing 2.4 g of a non-volatile, non-electrolyte in 100 g water. The osmotic pressure of the solution at $27^\circ\text{C}$ is ($K_f$ for water = 1.86, assume molality = molarity)

Answer: B

💡 Solution & Explanation

The freezing point depression $\Delta T_f = 0.744^\circ\text{C}$. Molality $m = \Delta T_f / K_f = 0.744 / 1.86 = 0.4 \text{ m}$. Assuming molarity $\approx$ molality, $C = 0.4 \text{ M}$. Osmotic pressure $\pi = CRT = 0.4 \times 0.0821 \times 300 = 9.852 \text{ atm}$. Therefore, correct answer is B.

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