The boiling point of pure benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

$\Delta T_b = 354.11 - 353.23 = 0.88$ K. Using $\Delta T_b = K_b \times (w / (M \times W_{\text{kg}}))$, we have $0.88 = 2.53 \times (1.80 / (M \times 0.090)) = 2.53 \times (20 / M) = 50.6 / M$. Solving for M gives $M = 50.6 / 0.88 = 57.5 \text{ g mol}^{-1}$. Therefore, correct answer is B.