A quantity of 10 g of solute 'A' and 20 g of solute 'B' is dissolved in 500 ml water. The solution i — Solutions and Colligative Properties Chemistry Question
Question
A quantity of 10 g of solute 'A' and 20 g of solute 'B' is dissolved in 500 ml water. The solution is isotonic with the solution obtained by dissolving 6.67 g of 'A' and 30 g of 'B' in 500 ml water at the same temperature. The ratio of molar masses, $M_A:M_B$, is
Answer: C
💡 Solution & Explanation
Since both solutions have the same volume (500 ml) and are isotonic, their total moles of solute must be equal. $10/M_A + 20/M_B = 6.67/M_A + 30/M_B$. Rearranging gives $(10 - 6.67)/M_A = (30 - 20)/M_B \Rightarrow 3.33/M_A = 10/M_B \Rightarrow M_A/M_B = 3.33/10 \approx 1/3$. Therefore, correct answer is C.
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