At a particular temperature and at a pressure of 1 atm, the mass and volume of that can be dissolved in 1 L of is ‘m’ gram and ‘V’ ml, respectively. Assuming that the solution obeys Henry’s law, the m

Question

At a particular temperature and at a pressure of 1 atm, the mass and volume of $O_3$ that can be dissolved in 1 L of $H_2O$ is ‘m’ gram and ‘V’ ml, respectively. Assuming that the solution obeys Henry’s law, the mass and volume of $O_3$ dissolved in 2 L of water at the same temperature and at 5 atm, will be

Prashant Kotian · Accepted Answer

Correct answer: C. Solubility (mass) is directly proportional to pressure and solvent volume. Mass in 2 L at 5 atm = . The volume of a dissolved gas is independent of pressure (because and , so cancels out), but it is proportional to the volume of the solvent. Thus, the volume dissolved in 2 L of water is . Therefore, correct answer is C.

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