The degree of dissociation () of a weak electrolyte, , is related to Van’t Hoff factor (i) by the ex — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

The electrolyte $\text{A}_x \text{B}_y$ dissociates into $x$ A ions and $y$ B ions, meaning $n = x + y$. The formula relating degree of dissociation $\alpha$ to the van't Hoff factor is $i = 1 + (n - 1)\alpha$. Substituting $n$, we get $i = 1 + (x + y - 1)\alpha \Rightarrow \alpha = (i - 1) / (x + y - 1)$. Therefore, correct answer is A.