The rise in the boiling point of a solution containing 1.8 g of glucose in 100 g of a solvent is . T — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Moles of glucose = $1.8 \text{ g} / 180 \text{ g/mol} = 0.01 \text{ mol}$. Molality $m = 0.01 \text{ mol} / 0.1 \text{ kg} = 0.1 \text{ m}$. Using $\Delta T_b = K_b \times m$, we have $0.1 = K_b \times 0.1$, which yields $K_b = 1 \text{ K/m}$. Therefore, correct answer is A.