A solution containing 2.60 g of a non-volatile, non-electrolyte solute in 200 g of water boils at at — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

The boiling point elevation $\Delta T_b = 100.130^\circ\text{C} - 100^\circ\text{C} = 0.130^\circ\text{C}$. Using the formula $\Delta T_b = K_b \times (w / (M \times W_{\text{kg}}))$, we get $0.130 = 0.52 \times (2.60 / (M \times 0.200))$. Rearranging for M gives $M = (0.52 \times 2.60) / (0.130 \times 0.200) = 52.0 \text{ g mol}^{-1}$. Therefore, correct answer is A.