Henry’s law constant for in water is at 298 K. The quantity of in 500 g of soda water when packed un — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

$p = K_H x$. $p = 3.2 \text{ bar} = 3.2 \times 10^5 \text{ Pa}$. $x = p / K_H = 3.2 \times 10^5 / 1.6 \times 10^8 = 2 \times 10^{-3}$. Moles of water $n_{H_2O} = 500 / 18 = 27.78 \text{ mol}$. $x = n_{CO_2} / (n_{CO_2} + n_{H_2O}) \approx n_{CO_2} / 27.78$. $n_{CO_2} = 2 \times 10^{-3} \times 27.78 = 0.05556 \text{ mol}$. Mass of $\text{CO}_2 = 0.05556 \times 44 \approx 2.44 \text{ g}$. Therefore, correct answer is A.