A solution having 54 g of glucose per litre has an osmotic pressure of 4.56 bar. If the osmotic pres — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

$\frac{\pi_1}{\pi_2} = \frac{C_1}{C_2}$. For glucose, $C_1 = 54/180 = 0.3$ M. $\frac{4.56}{1.52} = \frac{0.3}{C_2} \implies 3 = \frac{0.3}{C_2} \implies C_2 = 0.1$ M. Therefore, correct answer is D.