The relationship between osmotic pressure at 273 K when 10 g glucose (), 10 g urea () and 10 g sucro — Solutions and Colligative Properties Chemistry Question
Question
The relationship between osmotic pressure at 273 K when 10 g glucose ($\pi_1$), 10 g urea ($\pi_2$) and 10 g sucrose ($\pi_3$) are dissolved in 250 ml of water, is
Answer: C
💡 Solution & Explanation
Osmotic pressure depends on molarity ($\frac{\text{mass}}{M \cdot V}$). For constant mass and volume, $\pi \propto \frac{1}{M}$. Molar masses: Urea (60), Glucose (180), Sucrose (342). Since $60 < 180 < 342$, their moles are in the order Urea > Glucose > Sucrose. Thus, $\pi_2 > \pi_1 > \pi_3$. Therefore, correct answer is C.
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