How many grams of glucose, , should be dissolved in 0.5 kg of water at 25°C to reduce the vapour pre — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Using exact relative lowering: $\frac{P^\circ - P}{P} = \frac{n}{N} \implies \frac{1}{99} = \frac{w/180}{500/18} \implies w = \frac{500 \times 180}{99 \times 18} = 50.5$ g. Therefore, correct answer is A.