Addition of 4.0 g of a non-volatile solute to 54.0 g water results in a lowering of vapour pressure β Solutions and Colligative Properties Chemistry Question
Question
Addition of 4.0 g of a non-volatile solute to 54.0 g water results in a lowering of vapour pressure by 1.0%. What is the molar mass of the non-volatile solute?
Answer: A
π‘ Solution & Explanation
Using the exact relative lowering formula: $\frac{P^\circ - P}{P} = \frac{n}{N} \implies \frac{1}{99} = \frac{4/M}{54/18} = \frac{4/M}{3} \implies M = \frac{4 \times 99}{3} = 132$ g/mol. Therefore, correct answer is A.
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