Match the column (Solute in water vs Degree of dissociation to make Von't Hoff factor equal to 2) — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

The van't Hoff factor is $i = 1 + (n-1)\alpha$. The problem requires $i = 2$, so $2 = 1 + (n-1)\alpha$, which simplifies to $\alpha = 1/(n-1)$. For KCl ($n=2$), $\alpha = 1/1 = 1.00$ (Q). For $\text{Na}_2\text{SO}_4$ ($n=3$), $\alpha = 1/2 = 0.50$ (R). For $\text{K}_4[\text{Fe(CN)}_6]$ ($n=5$), $\alpha = 1/4 = 0.25$ (S). For $\text{K}_3[\text{Fe(CN)}_6]$ ($n=4$), $\alpha = 1/3 = 0.33$ (P). Therefore, correct answer is A-Q, B-R, C-S, D-P.