At , the osmotic pressure of urea solution is 500 mm. The solution is diluted and the temperature is — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Osmotic pressure $\pi = (n/V)RT$. For state 1: $\pi_1 = (n/V_1)RT_1 = 500 \text{ mm}$, $T_1 = 283 \text{ K}$. For state 2: $\pi_2 = (n/V_2)RT_2 = 105.3 \text{ mm}$, $T_2 = 298 \text{ K}$. Taking the ratio: $\pi_1 / \pi_2 = (V_2 / V_1) \times (T_1 / T_2)$. $500 / 105.3 = (V_2 / V_1) \times (283 / 298)$. Solving for the dilution ratio: $V_2 / V_1 = (500 / 105.3) \times (298 / 283) \approx 4.748 \times 1.053 \approx 5.0$. Therefore, correct answer is 5.