Solutions A and B have osmotic pressures of 2.4 atm and 4.2 atm, respectively, at a certain temperat — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Assuming additive volumes, the final osmotic pressure is a volume-weighted average of the initial osmotic pressures. Let the volume of B be $V$, then the volume of A is $2V$. Total volume = $3V$. $\pi_{mix} = \frac{\pi_A V_A + \pi_B V_B}{V_A + V_B} = \frac{2.4(2V) + 4.2(V)}{3V} = \frac{4.8 + 4.2}{3} = \frac{9.0}{3} = 3.0 \text{ atm}$. Therefore, correct answer is 3.