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A quantity of 2.0 g of benzoic acid dissolved in 26.0 g of benzene shows a depression in freezing poSolutions and Colligative Properties Chemistry Question

Question

A quantity of 2.0 g of benzoic acid dissolved in 26.0 g of benzene shows a depression in freezing point equal to 1.60 K. Molal depression constant of benzene is $4.88 \text{ K-kg mol}^{-1}$. The percentage association of the acid is

Answer: 0096

💡 Solution & Explanation

The theoretical molar mass of benzoic acid ($C_6H_5COOH$) is 122 g/mol. The observed molar mass $M_{obs} = (1000 \times K_f \times w) / (\Delta T_f \times W) = (1000 \times 4.88 \times 2.0) / (1.60 \times 26.0) = 9760 / 41.6 \approx 234.6 \text{ g/mol}$. The van't Hoff factor $i = M_{theo} / M_{obs} = 122 / 234.6 = 0.52$. For dimerization, $i = 1 - \alpha/2 \implies 0.52 = 1 - \alpha/2 \implies \alpha/2 = 0.48 \implies \alpha = 0.96$. The percentage association is 96%. Therefore, correct answer is 0096.

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