If the initial volume of vapours was , at what volume, the first drop of liquid will form? — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Using Boyle's Law ($P_1V_1 = P_2V_2$) for isothermal compression of the gas phase up to the dew point: $0.3 \text{ bar} \times 10.0 \text{ dm}^3 = 0.5 \text{ bar} \times V_2$. Solving for $V_2$ gives $V_2 = \frac{3.0}{0.5} = 6.0 \text{ dm}^3$. Therefore, correct answer is A.