In a cubic closest packed structure of mixed oxides, the lattice is made up of oxide ions. Tetrahedr — Solid State Chemistry Question
Question
In a cubic closest packed structure of mixed oxides, the lattice is made up of oxide ions. Tetrahedral voids are occupied by divalent $\text{X}^{2+}$ ions and octahedral voids are occupied by trivalent $\text{Y}^{3+}$ ions. If only 50% of the octahedral voids are occupied, then the percentage of tetrahedral voids occupied is
Answer: B
💡 Solution & Explanation
Let $\text{O}^{2-} = 4$ (CCP), giving total charge $-8$. 50% of 4 octahedral voids = 2 $\text{Y}^{3+}$ ions, contributing $+6$ charge. To achieve electrical neutrality, $+2$ charge is needed from $\text{X}^{2+}$, so there is 1 $\text{X}^{2+}$ ion. Total tetrahedral voids = 8. Percentage occupied = $(1 / 8) \times 100\% = 12.5\%$. Therefore, correct answer is B.
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