What is the void space per unit cell for metallic silver crystallizing in the FCC system, the edge l — Solid State Chemistry Question

💡 Solution & Explanation

Volume of unit cell = $a^3 = 4^3 = 64 \text{ \AA}^3$. In FCC, packing fraction is 0.74, so void space fraction is $1 - 0.74 = 0.26$. Void space volume = $0.26 \times 64 = 16.64 \text{ \AA}^3$. Therefore, correct answer is D.