Silver (atomic mass = 108) has an atomic radius of 144 pm and density . To which type of cubic cryst — Solid State Chemistry Question

💡 Solution & Explanation

Using FCC lattice assumption: $a = 2\sqrt{2}r = 2.828 \times 1.44 \times 10^{-8} = 4.07 \times 10^{-8} \text{ cm}$. Density $d = \frac{4 \times 108}{6.022 \times 10^{23} \times (4.07 \times 10^{-8})^3} = \frac{432}{40.58} \approx 10.6 \text{ g/cm}^3$. This matches the given density, confirming it is FCC. Therefore, correct answer is C.