Solid StatehardMCQ SINGLE

Is there an expansion or contraction as iron transform from HCP to BCC? The atomic radius of iron isSolid State Chemistry Question

Question

Is there an expansion or contraction as iron transform from HCP to BCC? The atomic radius of iron is $125 \text{ pm}$ in HCP but $50\sqrt{2} \text{ pm}$ in BCC.

Answer: B

💡 Solution & Explanation

HCP volume per atom = $\frac{4\sqrt{2} r_{HCP}^3}{6} \times \text{(atoms per unit cell)} = 4\sqrt{2} (125)^3 \approx 11.04 \times 10^6 \text{ pm}^3$. BCC volume per atom = $\frac{32 r_{BCC}^3}{3\sqrt{3}} = \frac{32 (50\sqrt{2})^3}{3\sqrt{3}} \approx 2.17 \times 10^6 \text{ pm}^3$. The volume per atom decreases, indicating a contraction. Therefore, correct answer is B.

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