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What is the formula of the magnetic oxide of cobalt, used in recording tapes, that crystallizes withSolid State Chemistry Question

Question

What is the formula of the magnetic oxide of cobalt, used in recording tapes, that crystallizes with cobalt atoms occupying one-eighth of the tetrahedral holes and one half of the octahedral holes in a closest packed array of oxide ions?

Answer: D

💡 Solution & Explanation

Let oxide ions be $N$. Tetrahedral voids = $2N$, octahedral voids = $N$. Co in tetrahedral = $\frac{1}{8} \times 2N = \frac{N}{4}$. Co in octahedral = $\frac{1}{2}N$. Total Co = $\frac{N}{4} + \frac{N}{2} = \frac{3N}{4}$. The ratio of Co:O is $\frac{3}{4} : 1 = 3 : 4$. The formula is Co$_3$O$_4$. Therefore, correct answer is D.

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