In a compound, oxide ions are arranged in CCP arrangement. Cations A occupy one-sixth of the tetrahe — Solid State Chemistry Question

💡 Solution & Explanation

Let the number of oxide ions (O) in CCP be 4. Tetrahedral voids = 8, so A = $\frac{1}{6} \times 8 = \frac{4}{3}$. Octahedral voids = 4, so B = $\frac{1}{3} \times 4 = \frac{4}{3}$. The ratio A:B:O is $\frac{4}{3} : \frac{4}{3} : 4$, which simplifies to 1:1:3. Thus, the formula is ABO$_3$. Therefore, correct answer is B.